-63+36t^2=108t

Solution for -63+36t^2=108t equation:

-63+36t^2=108t

We move all terms to the left:

-63+36t^2-(108t)=0

a = 36; b = -108; c = -63;
Δ = b2-4ac
Δ = -1082-4·36·(-63)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-144}{2*36}=\frac{-36}{72}
=-1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+144}{2*36}=\frac{252}{72}
=3+1/2
$